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	<title>Comments on: center from radius and two intersections</title>
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		<title>By: Nurm</title>
		<link>http://norman.rasmussen.co.za/25/center-from-radius-and-two-intersections/comment-page-1/#comment-135188</link>
		<dc:creator>Nurm</dc:creator>
		<pubDate>Mon, 10 Dec 2007 13:04:55 +0000</pubDate>
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		<description>Then: cy == y1 == y2 is true, and that means that cx = (y2 + y1) / 2.</description>
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<p>Then: cy == y1 == y2 is true, and that means that cx = (y2 + y1) / 2.</p>
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		<title>By: gary</title>
		<link>http://norman.rasmussen.co.za/25/center-from-radius-and-two-intersections/comment-page-1/#comment-135180</link>
		<dc:creator>gary</dc:creator>
		<pubDate>Mon, 10 Dec 2007 12:06:42 +0000</pubDate>
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		<description>What if y1 equals y2 (i.e. dy is zero)?</description>
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<p>What if y1 equals y2 (i.e. dy is zero)?</p>
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